CH 3 handout_page_5

CH 3 handout | page 5 | https://thedailydialectics.com/pdfs/education/calculus/calculus-2-2413-HCC/CH 3 handout/CH 3 handout.pdf

Find the location of the extrema of the function. 6) f(x) = 2x - 3x2/3 on the interval [-1, 3}. 2 _2xI/3 2 _ 2xI/3-2 x3 x1 x1/3 xl/3 f'(x)=0— 2x1/3-2=0>x1/3=1>x=1 f '(x) is not defined at x = 0, then f '(x) does not exist at x = 0. The critical numbers of f(x) in (-1, 3) are: x = 0 and x = 1. The…